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Andrew Borst
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Thanks Rob. You are correct about the area of the Hudson Bay, I had glanced at Wikipedia and the 4 million km^2 number was for the Bay and the surrounding area.
The CAB and the Hudson Bay are roughly the same area at 4 km^2. I am trying to come to grip with map distortions and throwing that tidbit out there for you all. It may look like there is relatively half the ice left in the Arctic but that is far from the truth.
Thanks, crandles. Circle, duh! Using the first equation, the sq km above 80N is ~3.9 M km^2. So 3.9 - 1 = 2.9 b/w 80N-85N. Divide that by 24 and that is how many sq km each 80-85N cell in the Bremen concentration graph represents (0.12 M km^2). That helps me a lot to translate these maps in actual numbers.
Yes, but I was only using the measurement for reference of size. I found an online calculator that gives me the distance b/w two sets of lat/long coordinates. It gives me the distance b/w 85N-0E and 90N-0E is 568km. Next, the distance b/w 87.5N-0E and 87.5N-90E is 393km (1/4th, had to use that since the calculator would take me through the NP). So 588 * 393 * 4 = ~875,000 KM^2 above 85N. Okay?
Sorry, 80N.
How many sq km are above 90N? Just trying to figure out if DMI drop is possible. TIA
Is that the first time Dr. Masters linked to this site, Neven? Good to see you recognized, I think this is one of the most interesting sites on the internet.